8x^2-32x+32=2x^2-32x+128

Solution for 8x^2-32x+32=2x^2-32x+128 equation:

Simplifying
8x2 + -32x + 32 = 2x2 + -32x + 128

Reorder the terms:
32 + -32x + 8x2 = 2x2 + -32x + 128

Reorder the terms:
32 + -32x + 8x2 = 128 + -32x + 2x2

Add '32x' to each side of the equation.
32 + -32x + 32x + 8x2 = 128 + -32x + 32x + 2x2

Combine like terms: -32x + 32x = 0
32 + 0 + 8x2 = 128 + -32x + 32x + 2x2
32 + 8x2 = 128 + -32x + 32x + 2x2

Combine like terms: -32x + 32x = 0
32 + 8x2 = 128 + 0 + 2x2
32 + 8x2 = 128 + 2x2

Solving
32 + 8x2 = 128 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
32 + 8x2 + -2x2 = 128 + 2x2 + -2x2

Combine like terms: 8x2 + -2x2 = 6x2
32 + 6x2 = 128 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
32 + 6x2 = 128 + 0
32 + 6x2 = 128

Add '-32' to each side of the equation.
32 + -32 + 6x2 = 128 + -32

Combine like terms: 32 + -32 = 0
0 + 6x2 = 128 + -32
6x2 = 128 + -32

Combine like terms: 128 + -32 = 96
6x2 = 96

Divide each side by '6'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}